（ただし１と２を合せて１２のような使い方は出来ません。）
56個の解法が見つかりました。
(((3+8)÷1)-1)=10
((1×(3+8))-1)=10
((1×3)+(8-1))=10
((1×3)-(1-8))=10
((1×8)+(3-1))=10
((1×8)-(1-3))=10
((1+1)×(8-3))=10
((3+(1×8))-1)=10
((3+(8-1))÷1)=10
((3+(8÷1))-1)=10
((3+8)-(1×1))=10
((3+8)-(1÷1))=10
((3-(1-8))÷1)=10
((3-1)+(1×8))=10
((3-1)+(8÷1))=10
((3÷1)+(8-1))=10
((3÷1)-(1-8))=10
((8+(1×3))-1)=10
((8+(3-1))÷1)=10
((8+(3÷1))-1)=10
((8-(1-3))÷1)=10
((8-1)+(1×3))=10
((8-1)+(3÷1))=10
((8-3)×(1+1))=10
((8÷1)+(3-1))=10
((8÷1)-(1-3))=10
(1×((3+8)-1))=10
(1×(3+(8-1)))=10
(1×(3-(1-8)))=10
(1×(8+(3-1)))=10
(1×(8-(1-3)))=10
(3+((1×8)-1))=10
(3+((8-1)÷1))=10
(3+((8÷1)-1))=10
(3+(1×(8-1)))=10
(3+(8-(1×1)))=10
(3+(8-(1÷1)))=10
(3-((1×1)-8))=10
(3-((1-8)÷1))=10
(3-((1÷1)-8))=10
(3-(1×(1-8)))=10
(3-(1-(1×8)))=10
(3-(1-(8÷1)))=10
(8+((1×3)-1))=10
(8+((3-1)÷1))=10
(8+((3÷1)-1))=10
(8+(1×(3-1)))=10
(8+(3-(1×1)))=10
(8+(3-(1÷1)))=10
(8-((1×1)-3))=10
(8-((1-3)÷1))=10
(8-((1÷1)-3))=10
(8-(1×(1-3)))=10
(8-(1-(1×3)))=10
(8-(1-(3÷1)))=10