（ただし１と２を合せて１２のような使い方は出来ません。）
49個の解法が見つかりました。
((1×(5+5))÷1)=10
((1×1)×(5+5))=10
((1×5)+(1×5))=10
((1×5)+(5÷1))=10
((1+(5+5))-1)=10
((1+5)+(5-1))=10
((1+5)-(1-5))=10
((1-1)+(5+5))=10
((1÷1)×(5+5))=10
((5+(1×5))÷1)=10
((5+(1+5))-1)=10
((5+(5÷1))÷1)=10
((5+5)×(1×1))=10
((5+5)×(1÷1))=10
((5+5)+(1-1))=10
((5+5)-(1-1))=10
((5+5)÷(1×1))=10
((5+5)÷(1÷1))=10
((5-1)+(1+5))=10
((5÷1)+(1×5))=10
((5÷1)+(5÷1))=10
(1×((5+5)÷1))=10
(1×(1×(5+5)))=10
(1×(5+(1×5)))=10
(1×(5+(5÷1)))=10
(1+((5+5)-1))=10
(1+(5+(5-1)))=10
(1+(5-(1-5)))=10
(1-((1-5)-5))=10
(1-(1-(5+5)))=10
(1÷(1÷(5+5)))=10
(5+((1×5)÷1))=10
(5+((1+5)-1))=10
(5+((5÷1)÷1))=10
(5+(1×(1×5)))=10
(5+(1×(5÷1)))=10
(5+(1+(5-1)))=10
(5+(1-(1-5)))=10
(5+(1÷(1÷5)))=10
(5+(5×(1×1)))=10
(5+(5×(1÷1)))=10
(5+(5+(1-1)))=10
(5+(5-(1-1)))=10
(5+(5÷(1×1)))=10
(5+(5÷(1÷1)))=10
(5-((1-1)-5))=10
(5-((1-5)-1))=10
(5-(1-(1+5)))=10