（ただし１と２を合せて１２のような使い方は出来ません。）
57個の解法が見つかりました。
((1×3)+(2+5))=10
((1×5)+(2+3))=10
((1+3)×(5÷2))=10
((1+3)÷(2÷5))=10
((2×3)+(5-1))=10
((2×3)-(1-5))=10
((2+(3+5))÷1)=10
((2+3)+(1×5))=10
((2+3)+(5÷1))=10
((2+5)+(1×3))=10
((2+5)+(3÷1))=10
((2÷1)+(3+5))=10
((3×(5-1))-2)=10
((3+(2+5))÷1)=10
((3+5)+(1×2))=10
((3+5)+(2÷1))=10
((3÷1)+(2+5))=10
((5×(1+3))÷2)=10
((5+(2×3))-1)=10
((5+(2+3))÷1)=10
((5-1)+(2×3))=10
((5÷1)+(2+3))=10
((5÷2)×(1+3))=10
(1×(2+(3+5)))=10
(1×(3+(2+5)))=10
(1×(5+(2+3)))=10
(1+(3×(5-2)))=10
(1-(3×(2-5)))=10
(2+((3+5)÷1))=10
(2+(1×(3+5)))=10
(2+(3+(1×5)))=10
(2+(3+(5÷1)))=10
(2+(5+(1×3)))=10
(2+(5+(3÷1)))=10
(3+((2+5)÷1))=10
(3+(1×(2+5)))=10
(3+(2+(1×5)))=10
(3+(2+(5÷1)))=10
(3+(5+(1×2)))=10
(3+(5+(2÷1)))=10
(5×((1+3)-2))=10
(5×((1+3)÷2))=10
(5×(1+(3-2)))=10
(5×(1-(2-3)))=10
(5×(3+(1-2)))=10
(5×(3-(2-1)))=10
(5+((2×3)-1))=10
(5+((2+3)÷1))=10
(5+(1×(2+3)))=10
(5+(2+(1×3)))=10
(5+(2+(3÷1)))=10
(5+(3+(1×2)))=10
(5+(3+(2÷1)))=10
(5-(1-(2×3)))=10
(5÷((3÷2)-1))=10
(5÷(2÷(1+3)))=10