【メイク10】1,2,3,9を10にする方法





1,2,3,9と四則演算(+−×÷)を使用して10にする方法を紹介します。これはMake10、切符パズルなどと言います。

(ただし1と2を合せて12のような使い方は出来ません。)

72個の解法が見つかりました。


(((3+9)-2)÷1)=10

(((3+9)÷1)-2)=10

((1×(3+9))-2)=10

((1×3)+(9-2))=10

((1×3)-(2-9))=10

((1×9)+(3-2))=10

((1×9)-(2-3))=10

((1+9)×(3-2))=10

((1+9)÷(3-2))=10

((3+(1×9))-2)=10

((3+(9-2))÷1)=10

((3+(9÷1))-2)=10

((3+9)-(1×2))=10

((3+9)-(2÷1))=10

((3-(2-9))÷1)=10

((3-2)×(1+9))=10

((3-2)+(1×9))=10

((3-2)+(9÷1))=10

((3÷1)+(9-2))=10

((3÷1)-(2-9))=10

((9+(1×3))-2)=10

((9+(3-2))÷1)=10

((9+(3÷1))-2)=10

((9-(2-3))÷1)=10

((9-2)+(1×3))=10

((9-2)+(3÷1))=10

((9÷1)+(3-2))=10

((9÷1)-(2-3))=10

(1×((3+9)-2))=10

(1×(3+(9-2)))=10

(1×(3-(2-9)))=10

(1×(9+(3-2)))=10

(1×(9-(2-3)))=10

(1+(9×(3-2)))=10

(1+(9÷(3-2)))=10

(1-(9×(2-3)))=10

(1-(9÷(2-3)))=10

(2×((9-1)-3))=10

(2×((9-3)-1))=10

(2×(9-(1+3)))=10

(3+((1×9)-2))=10

(3+((9-2)÷1))=10

(3+((9÷1)-2))=10

(3+(1×(9-2)))=10

(3+(9-(1×2)))=10

(3+(9-(2÷1)))=10

(3-((1×2)-9))=10

(3-((2-9)÷1))=10

(3-((2÷1)-9))=10

(3-(1×(2-9)))=10

(3-(2-(1×9)))=10

(3-(2-(9÷1)))=10

(9+((1×3)-2))=10

(9+((1+2)÷3))=10

(9+((3-1)÷2))=10

(9+((3-2)÷1))=10

(9+((3÷1)-2))=10

(9+(1×(3-2)))=10

(9+(1÷(3-2)))=10

(9+(2÷(3-1)))=10

(9+(3-(1×2)))=10

(9+(3-(2÷1)))=10

(9+(3÷(1+2)))=10

(9-((1×2)-3))=10

(9-((1-3)÷2))=10

(9-((2-3)÷1))=10

(9-((2÷1)-3))=10

(9-(1×(2-3)))=10

(9-(1÷(2-3)))=10

(9-(2-(1×3)))=10

(9-(2-(3÷1)))=10

(9-(2÷(1-3)))=10



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