【メイク10】1,3,4,9を10にする方法





1,3,4,9と四則演算(+−×÷)を使用して10にする方法を紹介します。これはMake10、切符パズルなどと言います。

(ただし1と2を合せて12のような使い方は出来ません。)

73個の解法が見つかりました。


(((4+9)-3)÷1)=10

(((4+9)÷1)-3)=10

((1×(4+9))-3)=10

((1×4)+(9-3))=10

((1×4)-(3-9))=10

((1×9)+(4-3))=10

((1×9)-(3-4))=10

((1+9)×(4-3))=10

((1+9)÷(4-3))=10

((1-3)×(4-9))=10

((3-1)×(9-4))=10

((4+(1×9))-3)=10

((4+(9-3))÷1)=10

((4+(9÷1))-3)=10

((4+9)-(1×3))=10

((4+9)-(3÷1))=10

((4-(3-9))÷1)=10

((4-3)×(1+9))=10

((4-3)+(1×9))=10

((4-3)+(9÷1))=10

((4-9)×(1-3))=10

((4÷1)+(9-3))=10

((4÷1)-(3-9))=10

((9+(1×4))-3)=10

((9+(4-3))÷1)=10

((9+(4÷1))-3)=10

((9-(3-4))÷1)=10

((9-3)+(1×4))=10

((9-3)+(4÷1))=10

((9-4)×(3-1))=10

((9÷1)+(4-3))=10

((9÷1)-(3-4))=10

(1×((4+9)-3))=10

(1×(4+(9-3)))=10

(1×(4-(3-9)))=10

(1×(9+(4-3)))=10

(1×(9-(3-4)))=10

(1+(9×(4-3)))=10

(1+(9÷(4-3)))=10

(1-(9×(3-4)))=10

(1-(9÷(3-4)))=10

(4+((1×9)-3))=10

(4+((9-3)÷1))=10

(4+((9÷1)-3))=10

(4+(1×(9-3)))=10

(4+(9-(1×3)))=10

(4+(9-(3÷1)))=10

(4-((1×3)-9))=10

(4-((3-9)÷1))=10

(4-((3÷1)-9))=10

(4-(1×(3-9)))=10

(4-(3-(1×9)))=10

(4-(3-(9÷1)))=10

(9+((1×4)-3))=10

(9+((1+3)÷4))=10

(9+((4-1)÷3))=10

(9+((4-3)÷1))=10

(9+((4÷1)-3))=10

(9+(1×(4-3)))=10

(9+(1÷(4-3)))=10

(9+(3÷(4-1)))=10

(9+(4-(1×3)))=10

(9+(4-(3÷1)))=10

(9+(4÷(1+3)))=10

(9-((1×3)-4))=10

(9-((1-4)÷3))=10

(9-((3-4)÷1))=10

(9-((3÷1)-4))=10

(9-(1×(3-4)))=10

(9-(1÷(3-4)))=10

(9-(3-(1×4)))=10

(9-(3-(4÷1)))=10

(9-(3÷(1-4)))=10



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