（ただし１と２を合せて１２のような使い方は出来ません。）
54個の解法が見つかりました。
((2+(3+7))-2)=10
((2+3)+(7-2))=10
((2+3)-(2-7))=10
((2+7)+(3-2))=10
((2+7)-(2-3))=10
((2-2)+(3+7))=10
((2÷2)×(3+7))=10
((3+(2+7))-2)=10
((3+7)×(2÷2))=10
((3+7)+(2-2))=10
((3+7)-(2-2))=10
((3+7)÷(2÷2))=10
((3-2)+(2+7))=10
((7+(2+3))-2)=10
((7-2)+(2+3))=10
(2×((3+7)÷2))=10
(2+((3+7)-2))=10
(2+(2×(7-3)))=10
(2+(3+(7-2)))=10
(2+(3-(2-7)))=10
(2+(7+(3-2)))=10
(2+(7-(2-3)))=10
(2-((2-3)-7))=10
(2-((2-7)-3))=10
(2-(2×(3-7)))=10
(2-(2-(3+7)))=10
(2÷(2÷(3+7)))=10
(3+((2×7)÷2))=10
(3+((2+7)-2))=10
(3+(2×(7÷2)))=10
(3+(2+(7-2)))=10
(3+(2-(2-7)))=10
(3+(2÷(2÷7)))=10
(3+(7×(2÷2)))=10
(3+(7+(2-2)))=10
(3+(7-(2-2)))=10
(3+(7÷(2÷2)))=10
(3-((2-2)-7))=10
(3-((2-7)-2))=10
(3-(2-(2+7)))=10
(7+((2×3)÷2))=10
(7+((2+3)-2))=10
(7+(2×(3÷2)))=10
(7+(2+(3-2)))=10
(7+(2-(2-3)))=10
(7+(2÷(2÷3)))=10
(7+(3×(2÷2)))=10
(7+(3+(2-2)))=10
(7+(3-(2-2)))=10
(7+(3÷(2÷2)))=10
(7-((2-2)-3))=10
(7-((2-3)-2))=10
(7-(2-(2+3)))=10